w^2-27w-170=0

Solution for w^2-27w-170=0 equation:

w^2-27w-170=0

a = 1; b = -27; c = -170;
Δ = b2-4ac
Δ = -272-4·1·(-170)
Δ = 1409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{1409}}{2*1}=\frac{27-\sqrt{1409}}{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{1409}}{2*1}=\frac{27+\sqrt{1409}}{2}
$